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(A) To determine which compound is both diamagnetic and coloured,we analyze each option:$1$. $K_2Cr_2O_7$: $Cr$ is in the $+6$ oxidation state ($d^0$

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$K_2Cr_2O_7$

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(A) To determine which compound is both diamagnetic and coloured,we analyze each option:$1$. $K_2Cr_2O_7$: $Cr$ is in the $+6$ oxidation state ($d^0$ configuration). It is diamagnetic but its colour arises from charge transfer,not $d-d$ transitions.$2$. $(NH_4)_2[TiCl_6]$: $Ti$ is in the $+4$ oxidation state ($d^0$ configuration). It is diamagnetic and colourless.$3$. $VOSO_4$: $V$ is in the $+4$ oxidation state ($d^1$ configuration). It is paramagnetic and coloured.$4$. $K_2Cr_2O_7$ is the correct answer because it is diamagnetic $(d^0)$ and coloured due to ligand-to-metal charge transfer $(LMCT)$.

Among the following,the compound that is both diamagnetic and coloured is

Similar Questions

Number of complexes from the following with an even number of unpaired $d$ electrons is . . . . . . . . . .
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[Given atomic numbers: $V=23, Cr=24, Fe=26, Ni=28, Cu=29$]

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